<pmbarnes@g...> wrote in message 
news:1138855015.046838.154100@g......
>I am pretty new to XSL. I'm trying to import the contents of a
> well-formed XML document into an XSL file during processing. Everything
> I've read on this says that the following should work:
>
> <xsl:copy-of select="document('header.xml')"/>
>
> But nothing happens. The Row elements in header.xml never get imported.
> I don't get any processing errors. I've also tried in the select
> attribute appending "/node()" and "/Header/node()" and a few other
> things.
>
> Here's the contents of header.xml:
>
> <?xml version="1.0" encoding="UTF-8"?>
> <Header xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
> xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet"
> xmlns:x="urn:schemas-microsoft-com:office:excel">
> <Row>
> <Cell ss:StyleID="s85"><Data ss:Type="String">Changes are not
> pushed back to InfoPath! </Data></Cell>
> <Cell ss:StyleID="s84"/>
> <Cell ss:StyleID="s84"/>
> </Row>
> <Row ss:AutoFitHeight="0" ss:Height="35.25">
> <Cell ss:StyleID="s48"><ss:Data ss:Type="String"
> xmlns="http://www.w3.org/TR/REC-html40"><B>CMS</B><Font> ::
> Hardware Quote</Font></ss:Data></Cell>
> </Row>
> </Header>
>
Try a simple stylesheet with just
<xsl:template match="/">
  <<xsl:copy-of select="document('header.xml')"/>
</xsl:template>

This assumes that both header.xml and the stylesheet are loaded from files 
in the same folder.

The other thing is which platform are you using?
If you're using .NET or the later Msxml versions then you'll need to set 
permisssions to allow use of the document function


-- 

Joe Fawcett (MVP - XML)

https://mvp.support.microsoft.com/profile=8AA9D5F5-E1C2-44C7-BCE8-8741D22D17A5