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Re: Modify the xsl stylesheet with an xslt parameter

From: "Joe Fawcett" <joefawcett@---------.------>
To: NULL
Date: 12/8/2005 8:26:00 AM
"lara0o" <larabox@g...> wrote in message 
news:1133964927.419653.7050@o......
> Hi,
>
> How can i modify the <xsl:stylesheet /> of an xsl file with a parameter
> given to the transformation?
> I mean, this doesn't work at all, we are all agree :
>
> <?xml version="1.0" encoding="UTF-8" ?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xs:param name="foo"/>
> <xsl:output method="xml" indent="yes"
> doctype-system="{$foo}/dtdfile.dtd" />
> <xsl:template match="foofoo">
> ...
>
> But this explains perfectly what a want to do: modify the dtd in
> function of the given parameter.
>
> Thx.
>
> 0o.
>
Well you could open the stylesheet as a DOM and make any changes before 
applying the transform.

-- 

Joe 




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