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Re: xsl lost reference with select="document('...

From: Martin Honnen <mahotrash@-----.-->
To: NULL
Date: 12/2/2005 8:06:00 PM

fausto wrote:


> The xsl was function well, the problem is when try to get a node of the
> original document
> into a foreach that references the xsl:document.
> 
> The value that i´ve got always is empty, i don´t know why.

Show us a minimal test case not working.
Unless you use .NET or MSXML 6, then first make sure you set up the 
transformation so that it executes document calls. With those 
implementations security settings might prevent document from having effect.
See
<http://msdn.microsoft.com/library/default.asp?url=/library/en-us/cpref/html/frlrfsystemxmlxslxsltransformclassloadtopic9.asp>
for .NET (1.x) and
<http://msdn.microsoft.com/library/default.asp?url=/library/en-us/xmlsdk/html/a2c8af20-3f3a-4f65-b2bd-7094a23eec02.asp>
for MSXML 6.


-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/


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