Dear Experts, Please tell me how can I do the xslt on multiple input file to 
one output file.these are the data files.

data.xml
<?xml version="1.0" ?>
<datas>
  <data>1</data>
  <data>2</data>
  <data>3</data>
</datas>

data2.xml
<?xml version="1.0" ?>
<datas>
  <data>7</data>
  <data>8</data>
  <data>9</data>
</datas>

data3.xml
<?xml version="1.0" ?>
<datas>
  <data>4</data>
  <data>5</data>
  <data>6</data>
</datas>

and this is the transform i want to apply to each file
data.xslt
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
version="1.0">
  <xsl:output method="xml"/>
  <xsl:template match="/">
    <items>
      <xsl:apply-templates select="datas" />
    </items>
  </xsl:template>
  <xsl:template match="data">
    <item>
      <xsl:value-of select="."/>
    </item>
  </xsl:template>
</xsl:stylesheet>

however if i have the list of data files like this
list.xml
<?xml version="1.0" ?>
<files>
  <file>data.xml</file>
  <file>data2.xml</file>
  <file>data3.xml</file>
</files>

how can i do transform each data file and make all output summarized in one 
output file like this (please noted that i need to do sorting)output.xml
<?xml version="1.0" encoding="utf-8" ?>
<items>
  <item>1</item>
  <item>2</item>
  <item>3</item>
  <item>4</item>
  <item>5</item>
  <item>6</item>
  <item>7</item>
  <item>8</item>
  <item>9</item>
</items>Thank for your help.