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juergen wrote: > <xsl:variable name="PosNrs"> > <xsl:copy-of select="/root//posNr"/> > </xsl:variable> > > then: > > <xsl:for-each select="$PosNrs"> > ... > </xsl:for-each> > > But i get an error. why? Because the variable contains a result tree fragment as you used copy-of (<http://www.w3.org/TR/xslt#copy-of>). I think you simply want <xsl:variable name="PosNrs" select="/root//posNr" /> that way the variable contains a node set of <posNr> elements. -- Martin Honnen --- MVP XML http://JavaScript.FAQTs.com/

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Re: for-each problem