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| | | Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: Xsl pattern help... [Thread Next] Re: Xsl pattern help...To: NULL Date: 7/7/2005 5:31:00 PM Chris, The way I'm doing it didn't work as easily as I would have hoped but I did get it to work. For some reason I needed to use the XPathNavigator object et al to do what I needed. thanks again for the help. King "Chris Lovett" wrote: > Well assuming you already did selectNodes("//Item") then for each > IXMLDOMNode that you get back just do the following: > > Dim name as string > name = node.parentNode.nodeName > > Then see if this string is equal to "Available" or "NotAvailable". > > > "K. Wilder" <KWilder@d...> wrote in message > news:5C021AE1-1399-42C6-BC0E-2330711AD300@m...... > > Chris, > > > > Thanks for the information. I apologize for not being completely clear, I > > failed to say that I needed this as XPath pattern to be used in VB.Net. > > > > Such as, selectSingleNode([pattern goes here]) > > > > I didn't mean for it to be used with an XSL stylesheet. My bad. > > > > It doesn't seem that name() or other node queries work in XPath > > expressions. > > Is there a way of doing what I want in an XPath expression? > > > > Thanks again, > > > > King Wilder > > > > "Chris Lovett" wrote: > > > >> Well, once you've found the matching <Item> element, the XPath query ".." > >> will select the parent element which is <Available> or <NotAvailable> so > >> the > >> relative query "name(..)" will return the name of this parent. So the > >> following XSL stylesheet: > >> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > >> version="1.0" > > >> <xsl:template match="/"> > >> <xsl:apply-templates select="//Item"/> > >> </xsl:template> > >> <xsl:template match="Item"> > >> <xsl:value-of select="."/>=<xsl:value-of > >> select="name(..)"/><xsl:text> > >> </xsl:text> > >> </xsl:template> > >> </xsl:stylesheet> > >> > >> Produces the following output: > >> Dog=Available > >> Cat=Available > >> Horse=Available > >> Bird=NotAvailable > >> Lizard=NotAvailable > >> Fish=NotAvailable > >> > >> > >> > >> "K. Wilder" <KWilder@d...> wrote in message > >> news:B4835EE1-6643-45FC-890D-494C268C39E8@m...... > >> >I have this xml... > >> > > >> > <Root> > >> > <Body> > >> > <Available> > >> > <Item>Dog</Item> > >> > <Item>Cat</Item> > >> > <Item>Horse</Item> > >> > </Available> > >> > <NotAvailable> > >> > <Item>Bird</Item> > >> > <Item>Lizard</Item> > >> > <Item>Fish</Item> > >> > </NotAvailable> > >> > </Body> > >> > </Root> > >> > > >> > I want to find which node, (Available or NotAvailable) any particular > >> > Item > >> > is in. Example: If I'm looking for "Fish" I want it to return > >> > NotAvailable. > >> > > >> > I can't quite figure this one out. > >> > > >> > Any help is appreciated. > >> > > >> > Thanks, > >> > > >> > King Wilder > >> > >> > >> > > > | |
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