you can use the following XPath expression to process those nodes 
separately:
<xsl:if test="s:Schema/s:ElementType/s:AttributeType/s:datatype/@dt:type = 
'dateTime'>
......process the node.........
</xsl:if>

thanks,
swapna

"Deck" <bldecker@i...> wrote in message 
news:%23vkAB0uZFHA.1448@T......
> This is a cross post.  I originally posted this question in the dotnet.xml 
> group.
>
> Hello,
>
> I am trying to find a way to format an XML attribute using XSL.  I want to
> run the format based on the datatype of the attribute.
>
> I need to remove everything from the "-" in a attribute that is defined as 
> a
> datetime.  I cannot go by the actual attribute name I need to process 
> based
> on data type.  Any assistance would be greatly appreciated.
>
> <s:Schema id="RowsetSchema">
>    <s:ElementType name="row" content="eltOnly" rs:updatable="true">
>    ... more attributes just not showing them all...
>        <s:AttributeType name="BirthDate" rs:number="3">
>            <s:datatype dt:type="dateTime" dt:maxlength="-1"
> rs:maybenull="True" />
>        </s:AttributeType>
>    </s:ElementType>
> </s:Schema>
> <rs:data>
>    <z:row BirthDate="1913-08-08T00:00:00.0000000-05:00" />
>    <z:row BirthDate="1920-08-08T00:00:00.0000000-06:00" />
>    <z:row BirthDate="1921-08-08T00:00:00.0000000-05:00" />
>    <z:row BirthDate="1925-08-08T00:00:00.0000000-06:00" />
>    <z:row BirthDate="1918-08-08T00:00:00.0000000-05:00" />
>    <z:row BirthDate="1935-08-08T00:00:00.0000000-06:00" />
> </rs:data>
>
>
>
>