Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries [Thread Prev] >Thread Next - Re: XSL Transform by Data type XSL Transform by Data typeTo: NULL Date: 6/1/2005 4:01:00 PM This is a cross post. I originally posted this question in the dotnet.xml
group.
Hello,
I am trying to find a way to format an XML attribute using XSL. I want to
run the format based on the datatype of the attribute.
I need to remove everything from the "-" in a attribute that is defined as a
datetime. I cannot go by the actual attribute name I need to process based
on data type. Any assistance would be greatly appreciated.
<s:Schema id="RowsetSchema">
<s:ElementType name="row" content="eltOnly" rs:updatable="true">
... more attributes just not showing them all...
<s:AttributeType name="BirthDate" rs:number="3">
<s:datatype dt:type="dateTime" dt:maxlength="-1"
rs:maybenull="True" />
</s:AttributeType>
</s:ElementType>
</s:Schema>
<rs:data>
<z:row BirthDate="1913-08-08T00:00:00.0000000-05:00" />
<z:row BirthDate="1920-08-08T00:00:00.0000000-06:00" />
<z:row BirthDate="1921-08-08T00:00:00.0000000-05:00" />
<z:row BirthDate="1925-08-08T00:00:00.0000000-06:00" />
<z:row BirthDate="1918-08-08T00:00:00.0000000-05:00" />
<z:row BirthDate="1935-08-08T00:00:00.0000000-06:00" />
</rs:data>
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