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Re: How to transform recusrive XML data with XSL?

From: Martin Honnen <mahotrash@-----.-->
To: NULL
Date: 3/11/2005 1:59:00 PM

David Bowey wrote:


> I've the following "recursive" XML file...
> 
> ###### XML FILE ######
> 
> <?xml version="1.0" encoding="utf-8" ?>
> <Nodes>
>  <Node>
>   <text>Parent 1</text>
>   <Nodes>
>    <Node>
>     <text>Child 1</text>
>     <Nodes>
>      <Node>
>       <text>Grandchild 1</text>
>      </Node>
>     </Nodes>
>    </Node>
>    <Node>
>     <text>Child 2</text>
>    </Node>
>   </Nodes>
>  </Node>
>  <Node>
>   <text>Parent 1</text>
>   <Nodes>
>    <Node>
>     <text>Child 1</text>
>     <Nodes>
>      <Node>
>       <text>Grandchild 1</text>
>      </Node>
>     </Nodes>
>    </Node>
>    <Node>
>     <text>Child 2</text>
>    </Node>
>   </Nodes>
>  </Node>
> </Nodes>
> 
> ###### END XML FILE ######
> 
> How do I transform this XML data into XHTML bulleted list using XSL?

That is rather easy with XSLT, you simply write templates for each of 
the different elements you have above creating the needed XHTML elements 
(e.g. <ul>, <li>) and then recursively with apply-templates process the 
remaining nodes:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   xmlns="http://www.w3.org/1999/xhtml"
   version="1.0">

<xsl:output method="xml"
             indent="yes"
             encoding="UTF-8"
             doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"
 
doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"
             omit-xml-declaration="yes" />

<xsl:template match="/">
   <html xml:lang="en" lang="en">
     <head>
       <title>list</title>
     </head>
     <body>
       <xsl:apply-templates />
     </body>
   </html>
</xsl:template>

<xsl:template match="Nodes">
   <ul>
     <xsl:apply-templates />
   </ul>
</xsl:template>

<xsl:template match="Node">
   <li>
     <xsl:apply-templates />
   </li>
</xsl:template>

<xsl:template match="text">
   <span><xsl:value-of select="." /></span>
</xsl:template>

</xsl:stylesheet>

-- 

	Martin Honnen
	http://JavaScript.FAQTs.com/


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