Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: XSLT and displaying hyperlinks in XML [Thread Next] Re: XSLT and displaying hyperlinks in XMLTo: NULL Date: 3/10/2005 4:36:00 PM Isn't it too complicated?
Why not just replace < to "<" after transformation?
html = html.Replace ("<", "<");
html = html.Replace (">", ">");
"Xero" <barisseker@g...> wrote in message
news:1110310164.289472.257880@g......
> Martin, thanks so much! That's exactly what I needed.
>
> Quick note to the people who might use Martin's code. You will need to
> add a forward slash to the 2nd <xsl:copy> to close this tag.
>
> <xsl:template match="a">
> <xsl:copy>
> <xsl:apply-templates select="@* | node()" />
> <xsl:copy> <---------HERE, like this </xsl:copy>
> </xsl:template>
>
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