I know Xml parsers are supposed to convert CRLF's to LF only. But in the 
stylesheet below I can see CR's. So I tried to strip out CR's with a 
translate function. But when I do that, the LF's are gone too.
 The stylesheet below produces
T has LF's
   T has CR's
I am expecting
B has LF's
   B has CR's
   T has LF's
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
 xmlns:msxsl="urn:schemas-microsoft-com:xslt">
 <xsl:output method="text" />
 <xsl:variable name="T">Extensible Stylesheet Language Transformations. 
along with the XML Path.
This is a point
and another:
and yet another:
 </xsl:variable>
 <xsl:variable name="CR">&#x0D;</xsl:variable>
 <xsl:variable name="LF">&#x0A;</xsl:variable>
 <xsl:variable name="B"><xsl:value-of select="translate($T, $CR, 
'')"/></xsl:variable>
 <xsl:template match="/">
  <root>
   <xsl:if test="contains($B, $LF)">B has LF's
   </xsl:if>
   <xsl:if test="contains($B, $CR)">B has CR's
   </xsl:if>
   <xsl:if test="contains($T, $LF)">T has LF's
   </xsl:if>
   <xsl:if test="contains($T, $CR)">T has CR's
   </xsl:if>
  </root>
 </xsl:template>
</xsl:stylesheet>

If the translate function is something like <xsl:value-of 
select="translate($T, 'A', 'B')"/>
then CF and LF stays put.

Any ideas?  Thanks Mark B