On Tue, 8 Feb 2005 03:29:02 -0800, AJ <AJ@d...> wrote:

> I have an xml file with a data structure like:
> <?xml version="1.0"?>
> <tree>
>   <tree_node id="7" depth="0" parent="0" value="Test">
>     <tree_node id="8" depth="1" parent="7" value="Test Sub"/>
>     <tree_node id="9" depth="1" parent="7" value="Test Sub One">
>       <tree_node id="10" depth="2" parent="9" value="Test Sub Two"/>
>     </tree_node>
>   </tree_node>
> </tree>

> The xsl stylesheet will need to output the node selected and all its  
> ancestors.

Hi,

If I understood correctly, you'd like to have thsi output:
<tree>
    <tree_node id="7" depth="0" parent="0" value="Test">
       <tree_node id="9" depth="1" parent="7" value="Test Sub One"/>
    </tree_node>
</tree>

if the node with id 9 was the 'selected node'.


That can be achieved with a stylesheet like this:

<xsl:stylesheet version="1.1"  
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:key name="id" match="*" use="@id"/>

<xsl:param name="id" select="9"/>
<xsl:variable name="mynode" select="key('id',$id)"/>

<xsl:output method="xml" indent="yes"/>

<xsl:template match="node()|@*">
	<xsl:copy>
		<xsl:apply-templates select="@*|node()[descendant-or-self::*=$mynode]"/>
	</xsl:copy>
</xsl:template>

</xsl:stylesheet>


regards,
-- 
Using Opera's revolutionary e-mail client: http://www.opera.com/m2/