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Re: Treat last element differently

From: "Joe Fawcett" <joefawcett@-------.--->
To: NULL
Date: 2/5/2005 11:14:00 AM
"Jason" <jason@j...> wrote in message 
news:eNaKfiwCFHA.2568@T......
> The exact code you suggested doesn't work. Interestingly, I place:
>
> <xsl:value-of select="position()" />
> <xsl:value-of select="last()" />
>
> in the same location, position() = 2 for the first element, 4 for the 
> second and so on. The value of last() is always one greater than the 
> position of the final element. If I use:
>
> <xsl:if test="position() + 1 &lt; last()">
>  <xsl:text>,</xsl:text>
> </xsl:if>
>
> Then it works. However, I am now concerned by the initial value of 
> position() and why it increments by 2 each time. Can anyone explain this?
>
> Thank again,
>
> - Jason
>
>
This is because you called apply-templates with no select, thus processing 
ALL children. This includes text nodes The carriage returns after the field 
elements) which are affecting your counting and position. If you add 
select="field" you should see the difference.


-- 

Joe (MVP - XML)


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