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Re: Treat last element differently

From: Jason <jason@-----.-----.-----.--->
To: NULL
Date: 2/5/2005 8:55:00 AM
The exact code you suggested doesn't work. Interestingly, I place:

<xsl:value-of select="position()" />
<xsl:value-of select="last()" />

in the same location, position() = 2 for the first element, 4 for the 
second and so on. The value of last() is always one greater than the 
position of the final element. If I use:

<xsl:if test="position() + 1 &lt; last()">
  <xsl:text>,</xsl:text>
</xsl:if>

Then it works. However, I am now concerned by the initial value of 
position() and why it increments by 2 each time. Can anyone explain this?

Thank again,

- Jason


Neil Smith [MVP Digital Media] wrote:
> I wonder if a variation on this might work : 
> 
> <xsl:if test="position() &lt; last()">
> 	<xsl:text>,</xsl:text>
> </xsl:if>
> 
> If not, I did this last year somewhere so I'll dig out the code.
> Cheers - Neil
> 
> 
> On Sat, 05 Feb 2005 01:06:34 +1030, Jason
> <jason@j...> wrote:
> 
> 
>><xsl:text>,</xsl:text>
> 
>


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