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Re: RDF to HTML with XSLT

From: JasonBurr@-----------.---------.---
To: NULL
Date: 1/10/2005 7:53:00 AM
Joe,

I thought that was just if the output was going to be XML in this case its 
not. The xsl outputs html not xml. Should I still be doing the 
transformNodeToObject anyway (issues with the input and matching types of xml 
and xsl?) BTW what was posted works fine but I would be more than happy to 
change if that is the better method. 

Only ask cause I would like to understand.

Thanks again everyone,

Jason

"Joe Fawcett" wrote:

> "Jason Burr" <JasonBurr@d...> wrote in message 
> news:DB2E90AA-4691-4918-951D-9B8161D30C44@m......
> > Thanks everyone who pitched in to help me. I went back to some code I 
> > wrote a
> > while back that was a lot cleaner (for postal api's) and started from 
> > scratch
> > this seems to work just fine. This does not however end the issue as I 
> > have
> > the same problem on client side code and suspect it has to do more with 
> > which
> > xml object versions are being used. Anyway for anyone who may have looked 
> > at
> > this and wanted to know the solution here it is
> >
> > Response.Buffer = True
> > Response.charset = "utf-8"
> >
> > strXMLOut="<?xml version=""1.0"" encoding=""utf-8""?>" &_
> > "<rdf:RDF" &_
> > "        xmlns:rdf = ""http://www.w3.org/1999/02/22-rdf-syntax-ns#"" " &_
> > "        xmlns:dc  = ""http://purl.org/dc/elements/1.1/"" " &_
> > "        xmlns:mq  = ""http://musicbrainz.org/mm/mq-1.1#"" " &_
> > "        xmlns:mm  = ""http://musicbrainz.org/mm/mm-2.1#"">" &_
> > "<mq:FindArtist>" &_
> > "  <mq:depth>4</mq:depth>" &_
> > "  <mq:artistName>Portishead</mq:artistName>" &_
> > "</mq:FindArtist>" &_
> > "</rdf:RDF>"
> >
> > strUrl = "http://www.musicbrainz.org/cgi-bin/mq_2_1.pl"
> >
> > strXSLPath = Server.MapPath("music.xsl")
> >
> > Set xmlDoc = Server.CreateObject("MSXML.DOMDocument")
> > Set xmlhttp = Server.CreateObject("Msxml2.ServerXMLHTTP.3.0")
> > xmlhttp.open "POST", strUrl, false
> > xmlhttp.send strXMLOut
> >
> > strXMLReturn = xmlhttp.responseText
> > xmlDoc.validateOnParse = False
> > xmlDoc.loadXML(strXMLReturn)
> >
> > Set xmlhttp = Nothing
> >
> > 'Load the XML.
> > Set source = Server.CreateObject("MSXML2.DOMDocument.3.0")
> > source.async = false
> > source.resolveExternals = false
> > source.load(xmlDoc)
> >
> > 'Load the XSLT.
> > Set style = Server.CreateObject("MSXML2.DOMDocument.3.0")
> > style.async = false
> > style.resolveExternals = false
> > style.load(strXSLPath)
> > strOutPut = source.transformNode(style)
> >
> > Response.Write strOutPut
> >
> > Set xmlDoc = Nothing
> > Set source = Nothing
> > Set style = Nothing
> >
> 
> As Martin said don't response.write the xml, do:
> source.transformNodeToObject style, Response
> Response.flush
> response.end
> 
> -- 
> 
> Joe 
> 
> 
> 


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