Altova Mailing List Archives


Re: Grouping By Field, with only 3 columns in each row.

From: "rdcpro" <rdcpro@-------.--->
To: NULL
Date: 12/21/2004 4:14:00 PM
The problem is with this template:

<xsl:template match="IssuedCard" mode="row">
<tr>
<xsl:apply-templates select=". | following-sibling::*[DateIssued =
current()/DateIssued][position() &lt; $maxColCount]"/>
</tr>
</xsl:template>

note that following-sibling includes all sibling nodes in the original
nodeset, even those that do not meet the key condition.

Also I wanted to point out a potential problem with using this
uniqueness test:

IssuedCard[count(. | key('CardsIssuedByDateIssued', DateIssued)[1]) =
1]

If there are IssuedCard elements without a DateIssued child, they will
show up in the nodeset selected by that expression.  The reason is that


key('CardsIssuedByDateIssued', DateIssued)[1])

will return no node in this case, so the count of the current node plus
nothing is always one.  In your particular case this is probably not an
issue, but watch out for it when using muenchian grouping.  That's why
I still use the generate-id() approach myself, even though it's not
quite a fast on the processors I use.

Regards,
Mike Sharp

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