Well contains or starts with depending on what you want

LIKE 'find me%'

Might be better with starts-with(NODE,$like-string)

LIKE '%find me%'

Would be contains(NODE,$like-string)

I'm not aware of an end-with function so if you needed 

LIKE 'find-me%' 

You may need to do something like

NODE = substring(NODE,length(NODE)-length($like-string),length($like-string))

"David Carnes" wrote:

> (Also answered in microsoft.public.xml)
> Daniel:
> Use contains()
> 
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>   <xsl:output method='xml' indent='yes' omit-xml-declaration='yes' />
>   <xsl:template match="foo">
>     <foo>
>       <xsl:apply-templates select="bar"/>
>     </foo>
>   </xsl:template>
> 
>   <xsl:template match="bar[contains(@a, 'food')]">
>     <bar>
>       <xsl:attribute name="b">
>         <xsl:value-of select="@b"/>
>       </xsl:attribute>
>     </bar>
>   </xsl:template>
> </xsl:stylesheet>
> 
> HTH!
> Dave
> 
> 
> "Daniel" <softwareengineer98037@y...> wrote in message 
> news:eZwXTtevEHA.1308@T......
> > is there any sort of "like" operation in xpath? e.g. convert:
> > <foo>
> >    <bar a="21food" b="alex"/>
> >    <bar a="food" b="moly"/>
> >    <bar a="222222" b="ashley"/>
> >    <bar a="fffooddd" b="sam"/>
> > </foo>
> >
> > to
> >
> > <foo>
> >    <bar b="alex"/>
> >    <bar b="moly"/>
> >    <bar b="sam"/>
> > </foo>
> >
> > 
> 
> 
>