Hi,

Something like...

<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:key name="kDistinctID" match="/*/*/*/@*" use="."/>

<!-- key for determining if a given attribute has an an attribute in its -->
<!--  parent/parent with the same name and a value of 'mappable' -->
<xsl:key name="kIsMappable" match="@*[. = 'mappable']"
use="concat(generate-id(..),'|',name())"/>

<xsl:template match="/">
  <uniques>
    <xsl:for-each select="/*/*/*/@*[name() = 'id' or
key('kIsMappable',concat(generate-id(../..),'|',name()))][generate-id() =
generate-id(key('kDistinctID',.)[name() = 'id' or
key('kIsMappable',concat(generate-id(../..),'|',name()))])]">
      <unique id="{.}"/>
    </xsl:for-each>
  </uniques>
</xsl:template>
</xsl:stylesheet>


HTH
Marrow
http://www.marrowsoft.com - home of Xselerator (XSLT IDE and debugger)
http://www.topxml.com/Xselerator


"Daniel" <softwareengineer98037@y...> wrote in message
news:%235u3HcnqEHA.2924@T......
> Let me re explain my question better then:
>
> Basically I would like there to be two ways for an attributes to get into
> the output document.
> 1. If the attribute's elements parent has an attribute with the same name
> and a value of "mappable"
> 2. If the attribute is named "id"
>
> As for this resulting list of id's I would like it to be a unique list.
> For example:
> <foo>
>      <xs a="mappable" b="mappable" c="mappable">
>          <x id="1111" a="2222" c="3333" house="home">
>           <x id="4444" a="5555" c="6666" house="home">
>      </xs>
>      <ys j="mappable">
>          <y id="7777" j="8888" house="home">
>      </ys>
>  </foo>
>
>  to
>
>  <uniques>
>      <unique id="1111">
>      <unique id="2222">
>      <unique id="3333">
>      <unique id="4444">
>      <unique id="5555">
>      <unique id="6666">
>      <unique id="7777">
>      <unique id="8888">
>  </uniques>
>
>