Please try this XSL -

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl">

<xsl:output method="xml" encoding="UTF-8" indent="yes"/>
	
<xsl:variable name="month-map">
   <months>
      <month>
         <string>Jan</string>
         <number>1</number>
      </month>
      <month>
         <string>Feb</string>
         <number>2</number>
      </month>
      <month>
         <string>Mar</string>
         <number>3</number>
      </month>
      <month>
         <string>Apr</string>
         <number>4</number>
      </month>
      <month>
         <string>May</string>
         <number>5</number>
      </month>
      <month>
         <string>Jun</string>
         <number>6</number>
      </month>
      <month>
         <string>Jul</string>
         <number>7</number>
      </month>
      <month>
         <string>Aug</string>
         <number>8</number>
      </month>
      <month>
         <string>Sep</string>
         <number>9</number>
      </month>
      <month>
         <string>Oct</string>
         <number>10</number>
      </month>
      <month>
         <string>Nov</string>
         <number>11</number>
      </month>
      <month>
         <string>Dec</string>
         <number>12</number>
      </month>
   </months>
</xsl:variable>
	
<xsl:template match="@* | node()">
   <xsl:copy>
      <xsl:apply-templates select="@*"/>
      <xsl:apply-templates select="node()"/>
   </xsl:copy>
</xsl:template>
	
<xsl:template match="field2">
    <xsl:variable name="mnth" select="substring-before(., '.')"/>
    <xsl:variable name="date" select="substring-before(substring-after(., ' 
'), ' ')"/>
    <xsl:variable name="year" select="substring-after(substring-after(., ' 
'), ' ')"/>
    <field2>
        <xsl:value-of select="msxsl:node-set($month-map)/months/month[string 
= $mnth]/number"/>/<xsl:value-of select="$date"/>/<xsl:value-of 
select="$year"/>
    </field2>
</xsl:template>
	
</xsl:stylesheet>

Regards,
Mukul


"JZYCN2" wrote:

> Hi 
> I have record sets in XML like following
> <field1>j3456</field1><field2>Aug. 23 2004</field2>....
> <field1>jhgert</field1><field2>Aug. 21 2004</field2>...
> <field1>j12dfg</field1><field2>Aug. 12 2004</field2>..
> .....
> 
> Now I want to display field2 different way lile format in 8/23/2004 way and 
> other fields I want to display as it is.  Can anyone advise how to do it.
> 
> Thanks a bunch in advance