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| | | Altova Mailing List Archives>Archive Index >microsoft.public.xsl Archive Home >Recent entries >Thread Prev - Re: XML and Viewlink component >Thread Next - Re: XML and Viewlink component Re: XML and Viewlink componentTo: NULL Date: 8/5/2004 5:08:00 PM Oleg,
Thanks for your reply.
I already tried <HTML xmlns:viewlink="dummy"> it helps with the error on
this line, but then I get an error in <VIEWLINK:bars> line.
I understand that <VIEWLINK:bars> is a name within VIEWLINK namespace, the
problem is that it's the only way I know to declare viewlink (DHTML
behavior) component. I don't need XML or XSL to process it, I just need them
to send it to HTML output as is. And so far I cannot find a way to do that.
Is there any way at all for this kind of situation?
Thanks,
Ilya Volodin
"Oleg Tkachenko [MVP]" <oleg@no_!spam!_please!tkachenko.com> wrote in
message news:uoQ%2375yeEHA.2468@T......
> Ilya Volodin wrote:
>
> > I'm trying to transform XML document into HTML using XSLT. But one of
the
> > tags should be transformed into viewlink tag. XSL doesn't allow me to
insert
> > <HTML xmlns:viewlink> instead of regular <HTML> tag into output. How can
I
> > go around it?
>
> <HTML xmlns:viewlink> isn't well-formed XML so you can't express it in
> XSLT. What about <HTML xmlns:viewlink="dummy">?
>
> > <VIEWLINK:bars> <--- If I use just <HTML> error in this line:
> > Desc - "Reference to undeclared namespace prefix: 'VIEWLINK'. Error
> > processing resource".
>
> In XML foo:bar name means namespace qualified name, where bar is local
> name and foo is namespace prefix, which must be declared.
>
> --
> Oleg Tkachenko [XML MVP]
> http://blog.tkachenko.com
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