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Re: [HELP] XSLT.Load Problem

From: tiraman@-----------.---------.---
To: NULL
Date: 8/1/2004 5:21:00 AM
Gr8 And Thanks For your help!


Best Regards,

T :-)


"Chris Barber" wrote:

> Hmm.
> 
> to be honest I can't see *any* reason why that wouldn't work without the number() function!
> 
> However, it is good practice to explicitly cast to a number when using string based information (as
> XML does) to ensure that you don't get funny results.
> 
> I'd suggest that it's a bug in the .NET system (not unlikely).
> 
> Chris.
> 
> "tiraman" <tiraman@d...> wrote in message
> news:C41832E5-9046-4A0E-95AB-1FF6656374F9@m......
> the variable define like this:
> <xsl:variable name="myCounter" select="count(/root/Category
> [@Type=18]/Child)"/>
> 
> and later in the xsl i m doing this kind of loop
> <xsl:for-each select="(Category)[(@Type='18')]">
> <TR VALIGN="BOTTOM">
>       <xsl:call-template name="Child1">
>                 <!-- please note that i added the number() function which solve me the
>                        problem which i didn't have in VB6 -->
> <xsl:with-param name="myCounter"
>                                          select="number(($myCounter))*2"/>
>       </xsl:call-template>
> </TR>
> </xsl:for-each>
> 
> 
> Best Regards,
> 
> T :-)
> 
> "Chris Barber" wrote:
> 
> > Post your XML (truncate to make it smaller if necessary) and XSL that shows this issue and I'll
> have
> > a look using Xselerator to see exactly what the variable / param contains - might point to a
> reason
> > for this.
> >
> > Chris.
> >
> > "Chris Barber" <chris@b...> wrote in message
> > news:uG7DxS2dEHA.996@T......
> > Is the variable a nodelist containing more than one element?
> > The number() function will then transform the first element value to a number thus allowing the
> > calculation?
> >
> > Chris.
> >
> > "tiraman" <tiraman@d...> wrote in message
> > news:E749BBFF-DF24-4E1F-90DA-615FD8841385@m......
> > hi,
> > you are right ! now it is working but as i wrote above it is wierd since
> >
> > it is working to me ok when i m doing transformation with vb6 but with
> >
> > vb .NET i have the problem if i m not using this function :-(
> >
> > so 1st thanks !
> >
> > 2nd if you have any idea why this happen i would like to know.
> >
> > Best Regards,
> >
> > T :-)
> >
> >
> > "Chris Barber" wrote:
> >
> > > You should probably ensure that the variable really is a number before attempting to use it in a
> > > calculation:
> > >
> > > <xsl:with-param name="myCounter" select="number(($myCounter))*2"/>
> > >
> > > Chris.
> > >
> > > "tiraman" <tiraman@d...> wrote in message
> > > news:F0F1F6D7-56EC-49C9-A3EA-A82E87212E6E@m......
> > > Hi,
> > >
> > > i have a problem to load xsl files which holds code like this:
> > >
> > >       <xsl:with-param name="myCounter" select="($myCounter)*2"/>
> > >
> > > but when i m removing the *2 every thing ok
> > >
> > >       <xsl:with-param name="myCounter" select="($myCounter)"/>
> > >
> > > Please note that this is working ok from VB6 using the
> > >
> > > Best Regards,
> > >
> > > T :-)
> > >
> > >
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> 
> 
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