Cary:
I think <xsl:template> and <xsl:apply-templates> will work for you.

Given this XML:
<data>
  <thing name="a"/>
  <thing name="d"/>
  <thing name="a"/>
</data>

...and this XSL:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method='text' indent='yes' omit-xml-declaration='yes' />
  <xsl:template name="data" match="data">
    <xsl:apply-templates select="thing[@name='a']"/>
    <xsl:apply-templates select="thing[@name!='a']"/>
  </xsl:template>

  <xsl:template match="thing[@name='a']">
    thing 1
  </xsl:template>

  <xsl:template match="thing[@name!='a']">
    thing 2
  </xsl:template>
  </xsl:stylesheet>

...will yield:

    thing 1

    thing 1

    thing 2

I leave the implementation up to you.  Have fun!
Oh, BTW, download Xselerator; it's a great tool.
http://www.marrowsoft.com/

Ciao,
Dave


"Cary Millsap" <cary.millsap@h...> wrote in message
news:10bs84hh6vspd63@c......
> I have a list L that contains values that are @name attribute values in
> elements of the input document. In my application, I need to traverse L,
> processing input document elements whose @name attribute values match
items
> from L. However, L doesn't contain all the names in the input document.
> Therefore, when I'm finished traversing L, I need to walk the input
document
> to process all the elements that weren't processed during the traversal of
> L. (There's a simplified example below my signature.)
>
> I can think of two ways to approach this problem, but I'm not sure which
is
> a more elegant XSL answer (or even if a way I'm not considering would be a
> smarter way to go):
>
> a) Attach an @has-been-processed attribute to the input document elements
as
> they're processed during the pass through L. (Is it even possible to do
this
> in XSL?)
>
> b) Whenever I process a set of elements in the input document, append
those
> elements' @id values in a separate data structure and then (somehow that I
> have yet to figure out) add a predicate that says "...and the element's
@id
> value is not in the already-processed list."
>
> Thank you very much for your advice.
>
>
> Cary Millsap
>
>
> Simplified example:
>
> - L contains the names "a" and "b".
> - Input document contains the following elements:
>     <thing name="a" .../>
>     <thing name="d" .../>
>     <thing name="a" .../>
>
> Step 1: For each element in L, process the input document's elements with
> that name. This pass will pick up the two 'a' elements. (I have figured
out
> already how to avoid emitting anything for 'b', since it is not
represented
> in the input document.)
> Step 2: For the input document elements that are left over, process those
> elements. This pass will pick up the 'd' element that was not addressed in
> Step 1.
>
>