I think you are trying to pass an expression, not a value as a parameter. If 
I'm correct,  this is impossible - XSLT doesn't support second order 
fuctions.
Yan

"Kai Cohrt" <kuewchen@g...> wrote in message 
news:59e96733.0405061552.454a3421@p......
> Hi there,
>
> I tried to find a solution on the newsgroup but even though lots of
> threads look at similar problems I could not find a solution.
>
> I have a xsl sheet that works fine this way:
>
> ...
> <xsl:variable name="rtf-sorted-nodeset">
> <xsl:for-each select="/Objects/SingleObject">
>  <xsl:sort 
> select="Attributes/Attr[DisplayName='Description']/DisplayValue"/>
>  <xsl:copy-of select="."/>
> </xsl:for-each>
> </xsl:variable>
>
> <!-- convert RTF to node-set -->
> <xsl:variable name="sorted-nodeset"
> select="msxsl:node-set($rtf-sorted-nodeset)/*"/>
> <xsl:template match="/">
> ...
>
> But if I want to pass in that sort value as parameter value I get into
> trouble with the 'Description' part of the XPath expression. I tried:
>
> <xsl:param name="paramSortAttr1"
> select='"Attributes/Attr[DisplayName='Description']/DisplayValue"'>
>
> and
>
> <xsl:param name="paramSortAttr1"
> select="'Attributes/Attr[DisplayName='Description']/DisplayValue'">
> and all kind of &quot; and &apos; combination.
>
> In the sort section I try to get the param value with
> <xsl:sort select="*[name() = $paramSortAttr1]"/>
>
> But like I said, the second approach does not work.
>
> Can anybody give me an idea what is wrong?
>
> Thank you very much,
> Kai