Hi there,

I tried to find a solution on the newsgroup but even though lots of
threads look at similar problems I could not find a solution.

I have a xsl sheet that works fine this way:

...
<xsl:variable name="rtf-sorted-nodeset">
 <xsl:for-each select="/Objects/SingleObject">
  <xsl:sort select="Attributes/Attr[DisplayName='Description']/DisplayValue"/>
  <xsl:copy-of select="."/>
 </xsl:for-each>
</xsl:variable>

<!-- convert RTF to node-set -->
<xsl:variable name="sorted-nodeset"
select="msxsl:node-set($rtf-sorted-nodeset)/*"/>
<xsl:template match="/">
...

But if I want to pass in that sort value as parameter value I get into
trouble with the 'Description' part of the XPath expression. I tried:

<xsl:param name="paramSortAttr1"
select='"Attributes/Attr[DisplayName='Description']/DisplayValue"'>

and

<xsl:param name="paramSortAttr1"
select="'Attributes/Attr[DisplayName='Description']/DisplayValue'">
and all kind of &quot; and &apos; combination.

In the sort section I try to get the param value with
<xsl:sort select="*[name() = $paramSortAttr1]"/>

But like I said, the second approach does not work.

Can anybody give me an idea what is wrong?

Thank you very much,
Kai