Yes, you just have to elect which children you want inside the node and code
the select="xpath" attributes of templates etc. accordingly.

I'll probably post some XSLT this evening to do that (busy at the moment
debugging GIS scripts).

Chris.


"Joe" <josephf@l...> wrote in message
news:fad90cce.0403040557.6dd3d70f@p......
Sorry about the code not being invalid...I wrote it quickly as a
proof-of-concept.

What if the code was more like

<?xml version="1.0"?>
<root>
  <Description/>
  <RegularMedia/>
  <SomeText/>
  <SidebarText1>Some Text</SidebarText1>
  <SidebarMedia1>some media.jpg</SidebarMedia1>
  <SomeMoreText/>
  <SomeMoreMedia/>
</root>

for example, with other sibling tags at the same level as the sidebar
tags, and I want the transformation to look like

<?xml version="1.0"?>
<root>
  <Description/>
  <RegularMedia/>
  <SomeText/>
  <Sidebar>
        <SidebarText1>Some Text</SidebarText1>
        <SidebarMedia1>some media.jpg</SidebarMedia1>
  </Sidebar>
  <SomeMoreText/>
  <SomeMoreMedia/>
</root>


Is this easily done?

Thanks,
Joe Finnamore




"Chris Barber" <chris@b...> wrote in message
news:<eYFgZeXAEHA.1032@T...>...
> Your XML is invalid of course (try it in Marrowsoft Xselerator) but the
> following should help you (an identity transform with template override
for
> the <root> node).
>
> This XML:
>
> <?xml version="1.0"?>
> <root>
>  <SidebarText1>Some Text</SidebarText1>
>  <SidebarMedia1>some media.jpg</SidebarMedia1>
> </root>
>
> with this XSLT:
>
> <?xml version="1.0"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>  <xsl:output method="xml" indent="yes" encoding="utf-16" />
>  <!-- Identity transform, passes nodes through untouched -->
>  <xsl:template match="@*|node()|text()">
>   <xsl:copy>
>    <xsl:apply-templates select="@*|node()|text()" />
>   </xsl:copy>
>  </xsl:template>
>  <!-- Match the root tag and add a new element with the children as
children
> of the new node -->
>  <xsl:template match="root">
>   <xsl:element name="{name(.)}">
>    <SideBar>
>     <!-- Now add all children of the root node to this new node -->
>     <xsl:copy-of select="./*"/>
>    </SideBar>
>   </xsl:element>
>  </xsl:template>
> </xsl:stylesheet>
>
> Gives:
>
> <?xml version="1.0" encoding="utf-16"?>
> <root>
>  <SideBar>
>   <SidebarText1>Some Text</SidebarText1>
>   <SidebarMedia1>some media.jpg</SidebarMedia1>
>  </SideBar>
> </root>
>
> Chris.
>
> "Joe" <josephf@l...> wrote in message
> news:fad90cce.0403031055.5bc75d13@p......
> Hi,
> I'm new to xsl, and I was wondering if someone knows how to change:
>
> <tag1>
> <tag2>
> <SidebarText1>Some Text</SidebarText1>
> <SidebarMedia1>some media.jpg</SidebarMedia1>
> ... (other tags starting with Sidebar)
> <tag3>
> <tag4>
>
>
> into
>
> <tag1>
> <tag2>
> <Sidebar>
>     <SidebarText1>Some Text</SidebarText1>
>     <SidebarMedia1>some media.jpg</SidebarMedia1>
>     ... (other tags starting with Sidebar)
> </Sidebar>
> <tag3>
> <tag4>
>
>
> ie. Take all tags starting with Sidebar and moving them as children of
> a generic tag called Sidebar.
>
>
> Thanks,
> Joe Finnamore