Altova Mailing List Archives


Re: Generating table

From: "Mark Goldin" <markgoldin@-------.--->
To: NULL
Date: 10/4/2003 2:08:00 PM
If I put "tr" into "tablerow" template then that will create a row for every
call to that template.
Thats' not what I want.

"Dimitre Novatchev" <dnovatchev@y...> wrote in message
news:bllq5h$dhl3o$1@I......
> > Problem is that second call to a template creates a row
> > with both West and East data. I want to have them in
> > different rows. Can someone help, please?
>
> Then put the "tr" element into the "tablerow" template -- not outside of
it.
>
>
> =====
> Cheers,
>
> Dimitre Novatchev.
> http://fxsl.sourceforge.net/ -- the home of FXSL
>
>
>
> "Mark" <markgoldin@c...> wrote in message
> news:0dfc01c38a00$1660edb0$a001280a@p......
> > XML:
> > <?xml version="1.0"?>
> > <?xml-stylesheet type="text/xsl" href="test.xsl"?>
> > <root>
> >  <categories>
> >   <category name="May" />
> >   <category name="June" />
> >   <category name="July" />
> >   <category name="August" />
> >   <category name="September" />
> >   <category name="October" />
> >   <category name="November" />
> >   <category name="December" />
> >   <category name="January" />
> >   <category name="February" />
> >   <category name="March" />
> >   <category name="April" />
> >   </categories>
> >  <dataset seriesname="EAST">
> >   <set value="310" />
> >   <set value="330" />
> >   <set value="323" />
> >   <set value="402" />
> >   <set value="391" />
> >   <set value="421" />
> >   <set value="373" />
> >   <set value="387" />
> >   <set value="403" />
> >   <set value="485" />
> >   <set value="545" />
> >   <set value="516" />
> >   </dataset>
> >  <dataset seriesname="WEST">
> >   <set value="261" />
> >   <set value="260" />
> >   <set value="271" />
> >   <set value="312" />
> >   <set value="329" />
> >   <set value="346" />
> >   <set value="341" />
> >   <set value="321" />
> >   <set value="298" />
> >   <set value="381" />
> >   <set value="435" />
> >   <set value="452" />
> >   </dataset>
> > </root>
> >
> > XSLT:
> > <?xml version='1.0'?>
> > <xsl:stylesheet
> > xmlns:xsl='http://www.w3.org/1999/XSL/Transform'
> > version='1.0'>
> >
> > <xsl:output method="html" version="4.0" />
> > <xsl:template match="/">
> > <html>
> > <table border="1" width="70%" style="font-size: 10pt;
> > border: 0.5 solid #000000" cellspacing="0"
> > cellpadding="0" bordercolor="#000000">
> > <tr>
> > <xsl:for-each select="//category">
> > <xsl:call-template name="tablerow">
> > <xsl:with-param name="value" select="@name" >
> > </xsl:with-param>
> > </xsl:call-template>
> > </xsl:for-each>
> > </tr>
> > </table>
> > <table border="1" width="70%" style="font-size: 10pt;
> > border: 0.5 solid #000000" cellspacing="0"
> > cellpadding="0" bordercolor="#000000">
> > <tr>
> > <xsl:for-each select="//set">
> > <xsl:call-template name="tablerow">
> > <xsl:with-param name="value" select="@value" >
> > </xsl:with-param>
> > </xsl:call-template>
> > </xsl:for-each>
> > </tr>
> > </table>
> > </html>
> > </xsl:template>
> >
> > <xsl:template name="tablerow">
> > <xsl:param name="value" />
> > <td style="border-right-style: solid; border-right-width:
> > 0.5">
> > <xsl:value-of select="$value" />
> > </td>
> > </xsl:template>
> > </xsl:stylesheet>
> >
> > Problem is that second call to a template creates a row
> > with both West and East data. I want to have them in
> > different rows. Can someone help, please?
> >
> > Thanks
>
>


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