Bob Alston wrote:
> I keep getting the error:  -2147024809  (80070057)  The parameter is
> incorrect
>
> Here is the XML text:
>
> <?xml version="1.0" encoding="utf-8"?>
> <soap12:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
<snip>
> </soap12:Envelope>
>
> Here is my VBA code:
>
> Private Sub Command2_Click()
>     Dim XMLConnectString As String
>
>     Dim XMLResponseText As String
>     Me.Responsetext = ""
>     XMLConnectString = Me.fld
>     'Create the xmlhttp object
<snip>
>     Call xmlhttp.send(XMLConnectString)
>
<snip>
> The error line is:    Call xmlhttp.send(XMLConnectString)
>
> Hopefully this is something simple.

Oh wait ... you can't pass a string. You have to pass an xmldocument:
dim xmlSend as msxml2.domdocument
set xmlsend = new msxml2.domdocument
xmlsend.loadxml XMLConnectString
Call xmlhttp.send(xmlsend)


I suggest you use "msxml2." rather than "Microsoft." to avoid xml parser
version issues.
And it doesn't really make a lot of difference but I only use
CreateObject in vbscript ... this definietly comes under the heading of
"personal preference".

-- 
HTH,
Bob Barrows