Answered in microsoft.public.xml. Please do not post independently to 
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-- 

Joe Fawcett (MVP - XML)
http://joe.fawcett.name
"SM" <sony.m.2007@g...> wrote in message 
news:c7d5b55c-c3f5-489f-af5f-3cd3828e7c1f@d......
> Hi,
> My xml sample data as below
>
> <a>
>  <b>
> <c test1 ="1">
>  <d> ass</d>
>  <e name="n1" number="12">
>    <row id="0">
>      <field name="valuetobetaken" type="string">
>        gfghg
>      </field>
>      <field name="test1" type="string1">
>        gfghg
>      </field>
>
>    </row>
>    <row id="1">
>      <field name="test2" type="string">
>        gfghg
>      </field>
>      <field name="test3" type="string1">
>        gfghg
>      </field>
>    </row>
>  </e>
> </c>
>  </b>
> </a>
> I need to take the attribute value of   name("valuetobetaken") from
> the element field using xslt
> <c test1 ="1">
>  <d> ass</d>
>  <e name="n1" number="12">
>    <row id="0">
>      <field name="valuetobetaken"
>
> my xslt file as below
>
> <?xml version="1.0" encoding="UTF-8" ?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>  <xsl:output method="xml"/>
>  <xsl:template match="/">
>    <xsl:variable name="test" select="." />
>    <xsl:for-each select ="$test/a/b">
>      <xsl:value-of select="c[@test1=1]/d[@name='n1'][@number=12]/row
> [@id=12]/field[@name]">
>
>      </xsl:value-of>
>    </xsl:for-each>
>
>  </xsl:template>
> </xsl:stylesheet>
>
> the output is always coming as blank as below
> <?xml version="1.0" encoding="utf-8"?>
>
> attribute value is missing in the output.
> is there any problem in the select statement of xsl?
> I would like to know, how to take the attribute value, element value
> of field for the above scenario
>
> Thanks,
> Sony
>