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Re: LINQ to XML

From: Martin Honnen <mahotrash@-----.-->
To: NULL
Date: 6/12/2008 4:06:00 PM


Scott M. wrote:
>> Here is how you can do it, using Joe's suggestion:
>>
>>             XElement desc = XElement.Load(@"file.xml");
>>             XElement data = XElement.Parse("<data>" + desc.Value + > 
>> "</data>");
>>             Console.WriteLine(data.Value);
> 
> I think this is close, but the XML is not in a file, so I can't use your 
> .Load() suggestion to establish the desc variable.  How could I do this with 
> XMl that is being brought in from a dynamic source? 

What is a "dynamic source"?

http://msdn.microsoft.com/en-us/library/system.xml.linq.xelement.load.aspx 
also has overloads taking a TextReader or an XmlReader.


If you have a string with XML then use
   XElement desc = XElement.Parse(stringWithXml);

-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/

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