Thanks again.. This XSL does not produce the same result - I am trying to use 
a variable for the element "UnixEmail". What's wrong?. Thanks.

******************
<xsl:stylesheet
   xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
   version="1.0">

   <xsl:param name="id" select="4"/>
   <xsl:param name="element-name" select="UnixEmail"/>

   <xsl:output method="xml"/>

   <xsl:template match="@* | node()">
     <xsl:copy>
       <xsl:apply-templates select="@* | node()"/>
     </xsl:copy>
   </xsl:template>

<xsl:template match="*">
     <xsl:choose>
       <xsl:when test="local-name() = $element-name">
     	<xsl:if test="@ID = $id">
       	<xsl:copy-of select="."/>
     	</xsl:if>
       </xsl:when>
       <xsl:otherwise>
       	<xsl:copy-of select="."/>
       </xsl:otherwise>
</xsl:choose>
   </xsl:template>
</xsl:stylesheet>
******************

"Martin Honnen" wrote:

> Ganesh Muthuvelu wrote:
> 
> > Thanks for your help. I have one question on this. Is it possible to have a 
> > variable name for the template "match"?.
> > The reason I am asking this is: The node "UnixEmail" is NOT static and may 
> > change dynamically, for example, it could be even the "Domain" node..
> > 
> > So, is it possible to have something like this n XSL:?
> > 
> > <xsl:template match=@DynamicNodeName>
> 
> No, that is not possible. With XSLT 1.0 you are not even allowed to use 
> variables in match pattersn.
> 
> With XSLT 2.0 you could use
>    <xsl:param name="element-name" select="'UnixEmail'"/>
> 
>    <xsl:template match="*[local-name() eq $element-name]">
> 
> There are currently three XSLT 2.0 processors, Saxon 9, AltovaXML, and 
> Gestalt.
> 
> 
> With XSLT 1.0 you need to check inside of your template e.g.
>    <xsl:template match="*">
>      <xsl:choose>
>        <xsl:when test="local-name() = $element-name">
> 
> 
> -- 
> 
> 	Martin Honnen --- MVP XML
> 	http://JavaScript.FAQTs.com/
>