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Re: problem with xhtml-tags after transformNode

From: Joerk <Olaf.Joerk@----.------.-------.-->
To: NULL
Date: 4/10/2008 11:44:00 PM
On 10 Apr., 13:35, Martin Honnen <mahotr...@yahoo.de> wrote:

Thanks for your answer.

> Joerk wrote:
> > I', trying to transform a xml-file with a node containing xhtml-code.
> > Here is the part of the schema:
>
> > <xs:element name="Nodename">
> >   <xs:complexType>
> >     <xs:sequence>
> >       <xs:any namespace="http://www.w3.org/1999/xhtml" minOccurs="1"
> > maxOccurs="unbounded"  processContents="lax"/>
> >     </xs:sequence>
> >     <xs:anyAttribute namespace="http://www.w3.org/1999/xhtml"/>
> >   </xs:complexType>
> > </xs:element>
>
> > When declaring the node as:
>
> > <Nodename>
>
> The schema says "Rechtsmittel" not "Nodename".

Was my fault when copy&pasting the text. The nodenames in the
schema and in the xml file are the same.

>
> >   <div xmlns="http://www.w3.org/1999/xhtml">
> >     <p><STRONG>Some text...</STRONG></p>
>
> Note that XHTML defines an element named 'strong' but not an element
> named 'STRONG'.
>

I got this html-code from a XHTML-Online Editor. So I thought, the
case
doesn't matter.

> >     ... more xhtml ...
> >   </div>
> > </Nodename>
>
> > I get only the text, without any formatting, table etc.
>
> > When writing the node content as CDATA, I get the xhtml-code as is
> > into my document.
>
> > How can I manage it, to get the paragraphs, tables and formattings as
> > defined in xhtml ?
>
> Can you show us the stylesheet? I assume you are using one as the
> subject mentions transformNode.
>

I'm creating my style sheets with StyleVision">StyleVision. So it's very long. I
think
I paste the part of the header and the relevant node. Hope this helps.

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/
Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema">
    <xsl:output version="1.0" encoding="UTF-8" indent="no" omit-xml-
declaration="no" media-type="text/html" />
    <xsl:template match="/">
        <html>
            <head>
                <title />
            </head>
            <body>
                <xsl:for-each select="GSW">

GSW is the root node.

:

<xsl:for-each select="Rechtsmittel">
  <span style="font-family:Arial; font-size:12pt; ">
    <xsl:apply-templates />
  </span>
</xsl:for-each>

>
>         Martin Honnen --- MVP XML
>        http://JavaScript.FAQTs.com/

Thank you for any hints.

Olaf


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