Joerk wrote:

> <xsl:for-each select="Rechtsmittel">
>   <span style="font-family:Arial; font-size:12pt; ">

As your 'Rechtsmittel' element can contain arbitrary XHTML I would not 
use a 'span' element as the container, rather a 'div' element. But that 
is more a question of proper HTML use and not of XML/XSLT.

>     <xsl:apply-templates />
>   </span>
> </xsl:for-each>

The xsl:apply-templates is fine but you also need templates to process 
any elements in the XHTML namespace e.g.
   <xsl:template match="xhtml:*"
                 xmlns:xhtml="http://www.w3.org/1999/xhtml">
     <xsl:element name="{local-name()}" namespace="">
       <xsl:apply-templates select="@* | node()"/>
     </xsl:element>
   </xsl:template>
and for attributes
   <xsl:template match="xhtml:*/@*"
                 xmlns:xhtml="http://www.w3.org/1999/xhtml">
     <xsl:copy/>
   </xsl:template>

The first template above takes XHTML elements and transforms them to 
HTML elements in no namespace. Alternatively if you want your stylesheet 
to create XHTML you could use xsl:copy-of
   <xsl:template match="xhtml:*"
                 xmlns:xhtml="http://www.w3.org/1999/xhtml">
     <xsl:copy-of select="."/>
   </xsl:template>

-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/