MyCross wrote:

> I have no idea how to approach this.  It's just an in-memory string
> with an XML fragment, not an XML document - can I use XSLT on that?

Here is a stylesheet that performs the sort:

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
   <xsl:output method="xml" indent="yes" omit-xml-declaration="yes"/>
   <xsl:template match="Trend">
     <xsl:copy>
       <xsl:apply-templates select="Score">
         <xsl:sort select="@PullDate" data-type="text"/>
       </xsl:apply-templates>
     </xsl:copy>
   </xsl:template>

   <xsl:template match="@* | node()">
     <xsl:copy>
       <xsl:apply-templates select="@* | node()"/>
     </xsl:copy>
   </xsl:template>

</xsl:stylesheet>

And here is some C#/.NET 2.0 sample code that uses XslCompiledTransform 
to take a string with XML input and to return a string with the 
transformation result:

     class MyTransformer
     {
         private XslCompiledTransform processor;

         public MyTransformer(string stylesheetUri)
         {
             processor = new XslCompiledTransform();
             processor.Load(stylesheetUri);
         }
         public string Transform(string input)
         {
             StringWriter output = new StringWriter();
             processor.Transform(XmlReader.Create(new 
StringReader(input)), null, output);
             return output.ToString();
         }
     }

Use like this:

             string exampleInput = @" <Trend>
   <Score PullDate=""2008-03-22T00:00:00"" Value=""768"" />
   <Score PullDate=""2007-11-28T00:00:00"" Value=""748"" />
  </Trend>";
             MyTransformer transformer = new 
MyTransformer(@"..\..\XSLTFile1.xslt");
             string result = transformer.Transform(exampleInput);

You could use the same MyTransformer object for several Transform calls.


-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/