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Subject: How can I use XSLT / Xpath to sort elements for display and treat the last one displayed differently?

From: admyc <admyc@-------.--->
To: NULL
Date: 1/8/2008 2:49:00 AM
Hello

I am trying to use XSLT to display an XML document on a web-browser.

The XML document has products that contain ingredients:
<product>
  <ingredients>
      <ingredient mass-order="2">apple juice</ingredient>
      <ingredient mass-order=1"">orange juice</ingredient>
      <ingredient mass-order="3">banana</ingredient>
  </ingredients>
</product>

I want the ingredients of each product displayed in sequence with the
lowest 'mass-order' ingredient first and the highest last etc. I also
want commas between the ingredients and a full-stop after the last one
like so:
Orange juice, apple juice, banana.

I used 'xsl:for-each' to loop through the ingredients and sorted the
ingredients by mass-order before using 'xsl:value-of' to display the
ingredient. I also added the following to the 'xsl:for-each' element:

<xsl:choose>
  <xsl:when test=". != ../ingredient[last()]">
  <span>, </span>
  </xsl:when>
  <xsl:otherwise>
  <span>.</span>
  </xsl:otherwise>
</xsl:choose>

However I expected this to put a '.' after the last displayed
ingredient but it actually puts it after the last ingredient in the
XML mark-up so that if it is not displayed last it still has a full-
stop after it.

Does anyone know how to achieve my goal?

To reiterate I want the ingredients sorted and then displayed with
commas after all but the last displayed ingredient which I want to
have a '.' after it.

Thanks

AM


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