"rote" <naijacoder@h...> wrote in message
news:eOGxNUZIIHA.484@T......
> I found out that i can't use replace but translate so i did
> <xsl:value-of select="translate(@Title,':   ','&#60;br&#62;')" />
> for example lets say the @title is : THE BOY IS GOOD:THE GIRL IS GOOD
> what i want o achieve is
> THE BOY IS GOOD
> THE GIRL IS GOOD
> But what i get now is :THE BOY IS GOOD<THE GIRL IS GOOD<

translate replaces one character with another.  You can't replace a
character with a set of characters.

<xsl:template name="colonToBR">
    <xsl:param name="input" />
    <xsl:choose>
        <xsl:when test="contains($input, ':')">
            <xsl:value-of select="substring-before($input, ':')" />
            <xsl:call-template name="colonToBR>
                <xsl:with-param name="input" select="substring-after($input,
':')" />
            </xsl:call-template>
            <br />
        </xsl:when>
        <xsl:otherwise>
            <xsl:value-of select="$input" />
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>

<xsl:call-template name="colonToBR">
    <xsl:with-param select="@title" />
</xsl:call-template>

Of course all this pre-supposes that colons in the title text aren't intend
to be colons.


-- 
Anthony Jones - MVP ASP/ASP.NET