Meelis Lilbok wrote:
> Yes i cant simly replace beacuse in one file node with id="2" can have
> "Hello"
> in second file id="2" may have "Hallo"
>
> I try to explain little bit more :=
>
> [template.xml]
> <test>
>    <t id="1">Tere</t>
>    <t id="2">Maailm</t>
>    <t id="3">Head aega!</t>
> </test>
>
> [user.xml]
> <test>
>    <t id="1">Hallo</t>
>    <t id="2">World</t>
> </test>
>
>
> After synchronizing user.xml must look like this
> <test>
>    <t id="1">Hello</t>

I assume you meant to type Hallo...

>    <t id="2">World</t>
>    <t id="3">Head aega!</t>
> </test>
>

If you get rid of all the XML noise, you will be left with name-value pairs 
(see DictionaryEntry in the help).

"1"    "Hallo"
"2"    "World"


If you then put the template DictionaryEntry items into a Hashtable (q.v.) 
followed by the values extracted from the user.xml file *but taking note of 
this from the Hashtable.Add method help*:

"The Item property can also be used to add new elements by setting the value 
of a key that does not exist in the Hashtable. For example: 
myCollection["myNonexistentKey"] = myValue. However, if the specified key 
already exists in the Hashtable, setting the Item property overwrites the 
old value. In contrast, the Add method does not modify existing elements."

then you will have a hashtable containing the merged data.


You can then take the data from the hashtable, add back in all the XML cr^W 
stuff as you Append it to a StringBuilder, then write back to disk. The 
whole operation should take about as long as it takes to double-click a 
mouse button.

' not checked, but this is how you'd re-build the XML
dim sb as new StringBuilder("<test>" & vbLF)
for each thing as DictionaryEntry in yourHashtable
    sb.Append(string.format("  <t id=""{0}"">{1}</t>" & vbLf, 
thing.key.tostring, thing.value.tostring))
next
sb.Append("</test>")
' now write the file

Any use?

Andrew