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Convert XMl to Excel using XLST

From: mark.macumber@-----.---
To: NULL
Date: 1/4/2006 8:34:00 PM
I have been Scowering the net to try to find how to convert a simple
XML file to an Excel workbook using XSLT. I have a basic outline
working, But I need extra help. My XML is as follows:

<?xml version="1.0"?>
<?xml-stylesheet type='text/xsl' href='conditionReport.xslt'?>
<AreasRoot>
	<room name="Entrance Hall">
		<item name="Doors">
			<roomIndex>0</roomIndex>
			<conditionBefore />
			<conditionAfter />
			<commentsBefore />
			<commentsAfter />
		</item>
		<item name="Security Door">
			<roomIndex>0</roomIndex>
			<conditionBefore>F</conditionBefore>
			<conditionAfter />
			<commentsBefore />
			<commentsAfter />
		</item>
	</room>

	<userDetails>
		<tennant address="123 Fake Street"
                              name="Mark"
                              landlord="DCK"
                              leaseDate="11/11/2005" />
	</userDetails>
</AreasRoot>


*********************************************************************************
End of XML - this is not part of the XML
*********************************************************************************

and here is the XSLT document I use to format the above: (called
conditionReport.xslt)

<?xml version="1.0" encoding="UTF-8" ?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:template match="/">
			<html>
				<head>
					<style>

					</style>
				</head>
				<body>
					<table border="1">
						<colgroup width="20" align="center"></colgroup>
						<colgroup width="135" align="left"></colgroup>
						<colgroup width="25" align="left"></colgroup>
						<colgroup width="25" align="left"></colgroup>
						<colgroup width="25" align="left"></colgroup>
						<colgroup width="250" align="left"></colgroup>
						<colgroup width="25" align="left"></colgroup>
						<colgroup width="25" align="left"></colgroup>
						<colgroup width="25" align="left"></colgroup>
						<colgroup width="250" align="left"></colgroup>
						<td>Room</td>
						<td>Item</td>
						<td>Good</td>
						<td>Fair</td>
						<td>Poor</td>
						<td>Other Items and Comments</td>
						<td>Good</td>
						<td>Fair</td>
						<td>Poor</td>
						<td>Other Items and Comments</td>
						<xsl:for-each select="AreasRoot/room">
							<tr>
								<td valign="top" rowspan="{count(item)}"
reference-orientation="90">
									<b>
										<xsl:value-of select="@name"/>
									</b>
								</td>
								<xsl:for-each select="item">
									<td>
										<xsl:value-of select="@name"/>
									</td>
									<td>
										<xsl:if test="./conditionBefore = 'G' ">
											x
										</xsl:if>
									</td>
									<td>
										<xsl:if test="./conditionBefore = 'F' ">
											x
										</xsl:if>
									</td>
									<td>
										<xsl:if test="./conditionBefore = 'P' ">
											x
										</xsl:if>
									</td>
									<td>
										<xsl:value-of select="commentsBefore"/>
									</td>
									<td>
										<xsl:if test="./conditionAfter = 'G' ">
											x
										</xsl:if>
									</td>
									<td>
										<xsl:if test="./conditionAfter = 'G' ">
											x
										</xsl:if>
									</td>
									<td>
										<xsl:if test="./conditionAfter = 'G' ">
											x
										</xsl:if>
									</td>
									<td>
										<xsl:value-of select="commentsAfter"/>
									</td>
									<xsl:if test="position() != last()">
										<xsl:text disable-output-escaping="yes">&lt;tr&gt;</xsl:text>
									</xsl:if>
								</xsl:for-each>
							</tr>
						</xsl:for-each>
					</table>
				</body>
			</html>
	</xsl:template>
</xsl:stylesheet>


****************************************************************************
End of XSLT document - this is not part of the XSLT document
****************************************************************************


so that works ok so far. I need some basic formatting done, but that
can be worried about at a leter date. As you can see in the XML there
is a element called userDetails. I need for the information stored in
this node the on a different worksheet, how do i do that? I just cant
seem to find an answer anywhere its driving me nuts!

Please help.
Cheers,
Mark


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