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Re: Howto: Extract namespace declarations from XML using XSLT and XPath 1.0?

From: Martin Honnen <mahotrash@-----.-->
To: NULL
Date: 8/1/2005 1:56:00 PM

olympus_mons@g... wrote:

> BTW, even if the default NS gets undeclared with xmlns="" by some node,
> it will not be listed.

The XSLT template I posted looks at the namespace axis and that does not 
contain any namespace nodes for xmlns="" as in that case there are no 
namespace nodes. As said if you want to find that then you would need to 
look into the document for elements in no namespace e.g.

<xsl:template match="/">
   <references>
     <xsl:for-each select="//namespace::*[not(. = ../../namespace::*)]">
       <ns uri="{.}" prefix="{local-name(.)}" />
     </xsl:for-each>
     <xsl:if test="//*[namespace-uri() = '']">
       <ns uri="" prefix="" />
     </xsl:if>
   </references>
</xsl:template>

-- 

	Martin Honnen --- MVP XML
	http://JavaScript.FAQTs.com/

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