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Re: DOM/SOM MSXML4 - How to get the appinfo of an XSD-Element

From: Martin Honnen <mahotrash@-----.-->
To: NULL
Date: 4/1/2005 2:19:00 PM

Martin Schmeller wrote:


> I need to know how I can get the appinfo of an XSD-Element.
> I user msxml4 and VB6.
> Is there a way with the DOM/SOM object model?

The solution is a bit odd in my view but the information in annotations 
in a schema element is exposed by allowing to write the annotation to a 
new XML DOM document for instance, using the method writeAnnotation. 
Then you can use normal DOM and/or XPath to access appinfo or 
documentation as needed.

Here is a simple example using JScript, the XML document just has a root 
element:

<?xml version="1.0" encoding="UTF-8"?>
<GOD
   xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
   xsi:noNamespaceSchemaLocation="test2005040101Xsd.xml">Kibo</GOD>

the schema for that is

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema
   xmlns:xs="http://www.w3.org/2001/XMLSchema"
   version="1.0">

<xs:element name="GOD" type="xs:string" fixed="Kibo">
   <xs:annotation>
     <xs:appinfo>The one and only.</xs:appinfo>
   </xs:annotation>
</xs:element>

</xs:schema>

the example JScript creates a DOMDocument and parses the XML file, then 
it gets the schema item defining the root element using the 
getDeclaration method, creates a new empty DOMDocument and calls the 
writeAnnotation method to fill it with the annotation info from the 
schema element. Then XPath is used to read out the text content of the 
first xs:appinfo element.

var xmlDocument = new ActiveXObject('Msxml2.DOMDocument.4.0');
xmlDocument.async = false;
var valid = xmlDocument.load('test2005040101.xml');

if (valid) {
   var rootElementType = 
xmlDocument.namespaces.getDeclaration(xmlDocument.documentElement);
   var annotationDocument = new ActiveXObject('Msxml2.DOMDocument.4.0');
   rootElementType.writeAnnotation(annotationDocument);
   annotationDocument.setProperty('SelectionNamespaces', 
'xmlns:xs="http://www.w3.org/2001/XMLSchema"');
   alert(annotationDocument.selectSingleNode('//xs:appinfo').text);
}
else {
   alert(xmlDocument.parseError.reason);
}

-- 

	Martin Honnen
	http://JavaScript.FAQTs.com/


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