Scott wrote:

>
> Dim sourceUrl, xmlDoc, xmlHttp
> sourceUrl = 
> "http://www.somesource.com/search?client=someclient&output=xml_no_dtd&q=computers&num=0&ad=w15&adtest=on&adpage=3&adsafe=high&ip=10.1.4.80&useragent=Mozilla/4.0%20(compatible;%20MSIE%206.0;%20Windows%20NT%205.2;%20.NET%20CLR%201.1.4322)"
> 
> Set xmlDoc	= Server.CreateObject("MSXML2.DOMDocument.4.0")
> Set xmlHttp = Server.CreateObject("MSXML2.XMLHTTP.4.0")
> 
> xmlHttp.open "GET", sourceUrl, False
> xmlHttp.setRequestHeader "Content-Type", "text/xml"

If you do a HTTP GET request you are not sending any request body thus 
you should not send the request header for Content-Type, there is no 
content.

> xmlHttp.send()

Setting the Content-Type above would only make sense if here you would 
send some XML e.g.
   xmlHttp.send("<root><child>Kibo</child></root>")
thus as already said above you shouldn't set the request header for 
Content-Type.

> Response.Write xmlHttp.responseText & "<br><br><br>" & chr(13) & chr(10)
> 
> xmlDoc.validateOnParse = false
> 
> xmlDoc.loadXML(xmlHttp.responseText)

There is no need to parse responseXML, you can simply use
   xmlHttp.responseXML
as that is automatically created. And if you parse responseText you 
might run into encoding related problems which do not occur if you 
simply use responseXML, a Msxml2.DOMDocument object.



-- 

	Martin Honnen
	http://JavaScript.FAQTs.com/