JS wrote:

> The closest I coud find was NodeList:
>      NodeList list = (NodeList) expression.evaluate(new 
> org.xml.sax.InputSource(path), javax.xml.xpath.XPathConstants.NODESET);
> 
>      for (Object obj : list) {
>        System.out.println((String)obj);
> 
>      }

I think
        for (int i = 0, int l = list.getLength(); i < l; i++)
        {
          XmlAttribute att = (XmlAttribute)list.getItem(i);
          System.out.println(att.getNodeValue());
        }
should do but I mostly use the W3C DOM with JavaScript so take the above 
as pseudo code, not as compiled Java code.

> Ok but if I use XPath 2.0 would I then get the full result set?

You get the full set of nodes even with XPath 1.0 if you use the right 
method that returns a node-set
.
The difference I mentioned is with taking the string value of a node-set 
(which the method you have implictly does) where XPath 1.0 takes the 
string value of the first node in the node-set.

I thought with XPath 2.0 you would get the string concatenation of all 
nodes in the sequence as what is the result you get with XSLT 2.0 and 
xsl:value-of but it looks to be more complicated, with XPath 2.0 
string(sequence-of-more-than-one-node) is not allowed. I don't know what 
that API you use would do with an XPath 2.0 implementation, I think 
Michal Kay's Saxon allows you to use that API with XPath 2.0 but he 
always recommends to use Saxon's own API tailored to the XPath 2.0 data 
model.


-- 

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/