"Martin Honnen" <mahotrash@y...> wrote in message 
news:4a3787e8$0$30232$9b4e6d93@n......
> JS wrote:
>
>>  From Java I am trying to print values for all elements where ID = "A":
>>
>>  public void test(){
>>    javax.xml.xpath.XPathFactory factory = 
>> javax.xml.xpath.XPathFactory.newInstance();
>>    javax.xml.xpath.XPath xpath = factory.newXPath();
>>    javax.xml.xpath.XPathExpression expression;
>>    String result;
>>    try {
>>      expression = xpath.compile("//content[@id =\"A\"]/@value");
>>      URL url = this.getClass().getClassLoader().getResource("test.xml");
>>      String path = url.toURI().getPath();
>>      result = expression.evaluate(new org.xml.sax.InputSource(path));
>>      System.out.println("result is = " + result);
>>    } catch (Exception e) {
>>      e.printStackTrace();
>>    }
>>  }
>>
>>
>> But only:
>>
>> 0_A
>>
>> is printed. Does "//" not mean that all 'content' elements are chosen?
>
> There is an overload
> http://xml.apache.org/xalan-j/apidocs/javax/xml/xpath/XPathExpression.html#evaluate(org.xml.sax.InputSource,%20javax.xml.namespace.QName)
> of the evaluate method where the second argument allows you to choose a 
> result different from a string so use that to select 
> javax.xml.xpath.XPathConstants.NODESET as the return type, then I think 
> you can cast the returned object to a DOM NodeList and iterate over that 
> node list to access all selected nodes.


The closest I coud find was NodeList:
      NodeList list = (NodeList) expression.evaluate(new 
org.xml.sax.InputSource(path), javax.xml.xpath.XPathConstants.NODESET);

      for (Object obj : list) {
        System.out.println((String)obj);

      }

But that object is not iterable.



>
> The method you currently use converts the selected node-set to a string 
> and that, with XPath 1.0, means you always get the string value of the 
> first node in the node-set.

Ok but if I use XPath 2.0 would I then get the full result set?