JS wrote:

>  From Java I am trying to print values for all elements where ID = "A":
> 
>  public void test(){
>    javax.xml.xpath.XPathFactory factory = 
> javax.xml.xpath.XPathFactory.newInstance();
>    javax.xml.xpath.XPath xpath = factory.newXPath();
>    javax.xml.xpath.XPathExpression expression;
>    String result;
>    try {
>      expression = xpath.compile("//content[@id =\"A\"]/@value");
>      URL url = this.getClass().getClassLoader().getResource("test.xml");
>      String path = url.toURI().getPath();
>      result = expression.evaluate(new org.xml.sax.InputSource(path));
>      System.out.println("result is = " + result);
>    } catch (Exception e) {
>      e.printStackTrace();
>    }
>  }
> 
> 
> But only:
> 
> 0_A
> 
> is printed. Does "//" not mean that all 'content' elements are chosen?

There is an overload
http://xml.apache.org/xalan-j/apidocs/javax/xml/xpath/XPathExpression.html#evaluate(org.xml.sax.InputSource,%20javax.xml.namespace.QName)
of the evaluate method where the second argument allows you to choose a 
result different from a string so use that to select 
javax.xml.xpath.XPathConstants.NODESET as the return type, then I think 
you can cast the returned object to a DOM NodeList and iterate over that 
node list to access all selected nodes.

The method you currently use converts the selected node-set to a string 
and that, with XPath 1.0, means you always get the string value of the 
first node in the node-set.


-- 

	Martin Honnen
	http://msmvps.com/blogs/martin_honnen/