On Apr 2, 5:56=A0am, Martin Honnen <mahotr...@yahoo.de> wrote:
> johkar wrote:
> > Assume XML parent element has lots of children that are all unique
> > element names. =A0Is the only way to loop through them to use a wildcar=
d
> > (*) for the element name in the for-each or apply-templates call? =A0I
> > am looking for efficiency because I am going to have to do this many
> > times in the XSLT and there could be hundreds of child element names
> > for any given parent element. =A0Note, I don't have control over the XM=
L
> > tree structure.
>
> > Xpath: =A0 /category/businesstype/*
>
> > <category>
> > =A0 =A0 =A0 <businesstype>
> > =A0 =A0 =A0 =A0 =A0 =A0 =A0 <specialty>Some text</specialty>
> > =A0 =A0 =A0 =A0 =A0 =A0 =A0 <bigbox>Some text></bigbox>
> > =A0 =A0 =A0 =A0 =A0 =A0 =A0 <internetonly>Some text</internetonly>
> > =A0 =A0 =A0 =A0 =A0 =A0 =A0 ...many many more nodes
> > =A0 =A0 =A0 </businesstype>
> > </category>
>
> I don't see any problem with using * if you want to process all element
> child nodes.
> If you prefer you can name each element (type) explicitly e.g. in 2.0
> you can do
> =A0 <xsl:template match=3D"businesstype">
> =A0 =A0<xsl:apply-templates select=3D"speciality, bigbox, internetonly"/>
> =A0 </xsl:template>
> or in 1.0 (and of course 2.0) you can do e.g.
> =A0 <xsl:template match=3D"businesstype">
> =A0 =A0<xsl:apply-templates select=3D"speciality | bigbox | internetonly"=
/>
> =A0 </xsl:template>
> You would need to test which version performs better with the XSLT
> processor of your choice.
>
> --
>
> =A0 =A0 =A0 =A0 Martin Honnen
> =A0 =A0 =A0 =A0http://JavaScript.FAQTs.com/- Hide quoted text -
>
> - Show quoted text -

Thanks for confirming and the tips.