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How to select only specific rows from xml using xsl

From: anywherenotes@-----.---
To: NULL
Date: 2/6/2009 10:10:00 AM
Hi,

I currently have the following xsl file:
 <xsl:stylesheet
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    version="1.0">
<xsl:output method="text" omit-xml-declaration="yes" indent="no"/>
<xsl:param name="user"  select = "''"/>
<xsl:template match="query">
	<xsl:choose>
		<xsl:when test="exception[name and contains(user,
$user)]">status="exception" user="<xsl:value-of select="user"/>"
exception="<xsl:value-of select="exception/name"/>"</xsl:when>
	</xsl:choose>
</xsl:template>
</xsl:stylesheet>

And this is the XML file:
<queries>
	<query id="123" chunk="0" desc="">
		<user>something</user>
		<exception>
			<name>bob</name>
			<description>some error</description>
			<time>2007-07-25 15:01:54</time>
		</exception>
	</query>
	<query id="456" chunk="0" desc="">
		<user>something else</user>
	</query>
</queries>

And my output is:
$ c:/axssrvr_380/bin/xsltproc sample.xsl sample.xml

        status="exception" user="something" exception="bob"

$

I'd like to get this:
$ c:/axssrvr_380/bin/xsltproc sample.xsl sample.xml
status="exception" user="something" exception="bob"
$

I'm not clear where the blank lines are coming from, if I pipe output
into 'wc', I get 3 lines, so it's not a long line that's wrapping
around, but rather 3 lines, where I would only expect to get 1.

Thank you.
Alex



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