On Jan 7, 12:26=A0pm, Martin Honnen <mahotr...@yahoo.de> wrote:
> paul_0...@yahoo.com wrote:
> > this is the version of xsltproc I am using so what ever will work this
> > this.
>
> libxslt is XSLT 1.0. But if all of those params are provided then XSLT
> 2.0 is not needed I think:
>
> =A0 =A0<xsl:param name=3D"id"/>
>
> =A0 =A0<xsl:param name=3D"pid"/>
>
> =A0 =A0<xsl:param name=3D"tid"/>
>
> =A0 =A0<xsl:template match=3D"/">
> =A0 =A0 <xsl:copy-of
> =A0 =A0 =A0 select=3D"root/query[content =3D concat('id=3D', $id, ';pid=
=3D', $pid,
> ';tid=3D', $tid)]"/>
> =A0 =A0</xsl:template>
>
> --
>
> =A0 =A0 =A0 =A0 Martin Honnen
> =A0 =A0 =A0 =A0http://JavaScript.FAQTs.com/


Sorry to bother you but this is what I have and it does not seem to be
working.

a.xsl

<xsl:stylesheet
   xmlns:xsl=3D"http://www.w3.org/1999/XSL/Transform"
   version=3D"1.0">

       <xsl:output method=3D"text"/>
       <xsl:strip-space elements=3D"*"/>

       <xsl:param name=3D"id" select =3D "'UNDEFINED'"/>
       <xsl:param name=3D"pid"  select =3D "'UNDEFINED'"/>
       <xsl:param name=3D"tid"  select =3D "'UNDEFINED'"/>

       <xsl:template match=3D"/">
               <xsl:copy-of select=3D"root/query[content =3D concat('id=3D'=
,
$id, ';p
d=3D', $pid, ';tid=3D', $tid)]"/>
       </xsl:template>

</xsl:stylesheet>

the single root element in my XML is <queries>

<queries>
  <query id=3D"8124-1228816866" chunk=3D"0" desc=3D"">
    <context>id=3D1005;pid=3D5208;tid=3D5400</context>
     <a>111</a>
     <b>222</b>
     <c>333</c>
 </query>
 <query id=3D"8124-1228816867" chunk=3D"0" desc=3D"">
    <context>id=3D1006;pid=3D5278;tid=3D5400</context>
     <a>444</a>
     <b>555</ba>
     <c>666</c>
   </query>
</queries>

I am calling it like this:

xsltproc --param id '1005' --param pid '5208' --param tid '5400' ./
a.xsl ./a.xml

Am I missing something?