felciano wrote:

> I've been trying to adapt a technique described at http://www.xefer.com/amazon/wishlist
> that shows how to iterate through such pages through recursive
> document() calls and a document counter:
> 
> <xsl:template name="counter">
>   <xsl:param name="total"/>
>   <xsl:param name="page"/>
> 
>   <xsl:variable name="lookup"
>     select="concat($lookup, '&amp;ProductPage=', $page)
> 
>   <xsl:if test="$page <= $total">
>     <xsl:apply-templates select="document($lookup)"/>
>     <xsl:call-template name="counter">
>       <xsl:with-param name="total" select="$total"/>
>       <xsl:with-param name="page" select="$page + 1"/>
>     </xsl:call-template>
>   </xsl:if>
> 
> </xsl:template>
> 
> This works, but I can't figure out how to sort the aggregate results.
> Each document's nodes are processed separately before the next page is
> retrieved. Is there a convention / idiom for how to handle sorting
> when iterating via recursion across multiple document() calls?

Instead of using xsl:apply-templates select="document($lookup)" during 
each template invocation you need to pass on those results the document 
call returns. So give your template a third parameter

<xsl:template name="counter">
   <xsl:param name="total"/>
   <xsl:param name="page"/>
   <xsl:param name="page-elements" select="/.."/>

   <xsl:variable name="lookup"
     select="concat($lookup, '&amp;ProductPage=', $page)

   <xsl:choose>
     <xsl:when test="$page <= $total">
       <xsl:call-template name="counter">
         <xsl:with-param name="total" select="$total"/>
         <xsl:with-param name="page" select="$page + 1"/>
         <xsl:with-param name="page-elements" select="$page-elements | 
document($lookup)/*"/>
       </xsl:call-template>
     </xsl:choose>
     <xsl:otherwise>
       <xsl:apply-templates select="$page-elements">
         <xsl:sort select="foo"/>
       </xsl:apply-templates/>
     </xsl:otherwise>
   </xsl:choose

</xsl:template>




-- 

	Martin Honnen
	http://JavaScript.FAQTs.com/