Arndt Jonasson wrote:
> Let's say we have a schema (maybe expressed in XML Schema, but not
> necessarily so), that allows this instance document:
> 
> <top>
>   <txt>This is text</txt>
>   <books>
>     <book>Tarzan</book>
>     <book>Harry Potter</book>
>   </books>
> </top>
> 
> The text /top/txt may be empty, and the element /top/books may have no
> children, so this instance document is also allowed:
> 
> <top>
>   <txt/>
>   <books/>
> </top>
> 
> I now want to write an XPath expression that selects all nodes that do
> not have children in the schema. It would always select /top/txt and
> it would never select /top/books, even in the second example above.
> 
> With XPath 1.0, this is not possible, since schema information is not
> used there. But can it be done in XPath 2.0? I find the standard
> document a bit forbidding, although I'm fairly well acquainted with
> the 1.0 document.

Even in the XSLT 2.0 data model the txt element has a child node, it is 
a text child node. So your description of saying does not have "children 
in the schema" is not very precise. Are you looking for elements which 
have a simple type in the meaning of the W3C schema language, meaning 
they have no child _elements_ and no attributes? I am not sure whether 
schema aware XSLT 2.0 allows you do detect elements which have a simple 
type respectively do distinguish in your stylesheet between elements 
having a simple type and those having a complex type. As far as I know 
all you can do is match an element based on its type and validate input 
or output elements based on a schema.

You might want to ask on the XSL mailing list 
http://www.mulberrytech.com/xsl/xsl-list/, spec writers and implementors 
like Michael Kay are regulars there so you should get a more qualified 
answer there than here.



-- 

	Martin Honnen
	http://JavaScript.FAQTs.com/