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Java SAX parser. How to get the raw XML code of the currently parsing event

From: PatlaDJ <patladj@-----.--->
To: NULL
Date: 7/2/2008 3:47:00 PM

Java SAX parser, please need a clue how to get the raw XML code of the
currently parsing event... needed for logging, debugging purposes.

Here's and example, letting me clarify exactly what i need: (see the
comments in source)

public void startElement(String uri, String localName, String qName,
Attributes attributes) throws SAXException {
//..Here... or maybe somewhere elsewhere I need on my disposal the raw
XML code of every XML tags received from the XML stream.
//.. I need simply to write them down in a log file, for debugging
purposes, while parsing.
//.. Can anyone give me a suggestion how can i do that logging while
the SAX parser only returns me the tagname and attributes. While
parsing I want to log the XML code for every tag in its 'pure form',
like it is comming from the server directly on the socket's input
reader.

			if ("p".equals(qName)) {
                                                         //Do
something...
			}

		}

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Java SAX parser. How to get the raw XML code of the currently parsing event