Joe Kesselman wrote:
> Jim Andersen wrote:
> > As you can see from mr p.lepins posting the solution
> > is far from "trivial".

As Joe Kesselman said, it does a bit more than you asked
for. Partly because I wasn't really sure what you were
asking for, your original post being just a bit sloppy,
and partly because I tend to introduce what I perceive as
useful techniques/good practices when I post solutions to
problems on the usenet. Still, it's trivial enough even
then.

The transformation I posted copies any XML document fed to
it, sorting any siblings with sort attribute by the value
of that attribute (it breaks just a bit if there are
sibling elements without sort attribute interspersed with
elements it's trying to sort).

> I'm not sure I agree; that solution strikes me as
> overcomplicated for the question you asked.
>
> "Produce a new levelone document, copying the child
> elements in sorted order."
>
> <xsl:stylesheet version="1.0"
>    xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
>    <xsl:template select="/levelone">
>      <levelone>
>        <xsl:for-each select="child">
>          <xsl:sort select="@sort"/>
>          <xsl:copy-of select=".">
>        </xsl:apply-templates>
>      </levelone>
>    </xsl:template>
> </xsl:stylesheet>

Being my usual obnoxious self, I cannot resist the
temptation to point out that, in my opinion:

<xsl:stylesheet version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:template match="/levelone">
    <xsl:copy>
      <xsl:apply-templates>
        <xsl:sort select="@sort"/>
      </xsl:apply-templates>
    </xsl:copy>
  </xsl:template>
  <xsl:template match="child">
    <xsl:copy-of select="."/>
  </xsl:template>
</xsl:stylesheet>

is only a bit more complicated, and better from the
standpoint of teaching the Arguably Right Thing.

-- 
Pavel Lepin